Question 640600
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Let *[tex \LARGE x] be the measure of the first side.  Then *[tex \LARGE 2x\ -\ 10] is the measure of the second side, and *[tex \LARGE x\ +\ 50] is the measure of the third side.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ (2x\ -\ 10)\ +\ (x\ +\ 50)\ =\ 684]


Solve for *[tex \LARGE x], then calculate *[tex \LARGE 2x\ -\ 10], and *[tex \LARGE x\ +\ 50].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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