Question 640598
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An additive identity, *[tex \LARGE I], is a number such that *[tex \LARGE \forall\ a\ \in\ \mathbb{R},\ a\ +\ I\ =\ a].  That means if you can find any number *[tex \LARGE a] where *[tex \LARGE a\ +\ 1\ \neq\ a], then 1 is NOT an additive identity.


Let *[tex \LARGE a\ =\ 2], then *[tex \LARGE a\ +\ 1\ =\ 2\ +\ 1\ =\ 3].  *[tex \LARGE 3\ \neq\ 2] therefore...what?


By the way, how much importance should I place on the fact that you spelled "please" with 5 'a's?  Does that make your question more important or higher priority than someone who only uses 2 or 3 'a's or, Mithra forbid!, spells it properly?  Should your question be overlooked by someone who uses even more vowels?


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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