Question 640544
A fraction; my numerator is an odd single digit, my denominator is prime
 and is greater than my numerator.
d > n
 My denominator is 5 less twice as large as my numerator.
d = 2n - 5
Just write it like this
{{{n/(2n-5)}}}
:
Start with the highest odd single digit, 9
{{{9/(2(9)-5)}}} = {{{9/13}}} seems to satisfy the requirements