Question 640537
{{{sqrt(x-3) -x=-3}}}


{{{sqrt(x-3)=-3+x}}}


{{{sqrt(x-3)=x-3}}}


{{{(sqrt(x-3))^2=(x-3)^2}}}


{{{x-3=(x-3)^2}}}


{{{x-3=x^2 - 6x + 9}}}


{{{0=x^2 - 6x + 9-x+3}}}


{{{0=x^2 - 7x + 12}}}


{{{x^2 - 7x + 12 = 0}}}


{{{(x-3)(x-4) = 0}}}


{{{x-3=0}}} or {{{x-4 = 0}}}


{{{x=3}}} or {{{x=4}}}


So the *possible* solutions are {{{x=3}}} or {{{x=4}}}


Make sure you check both of them (I'll let you do this) to actually confirm that they are true solutions.


Let me know if you have any questions.