Question 640274
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To begin with, you don't have an equation.  ALL equations have an equals sign in them asserting that one quantity is equal to another.  Hence the name, 'equation'.  In that you do not have an equation, I'll supply you with one:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ \frac{2}{x^2\ +\ 49}]


The denominator has no real number zeros, so no real numbers are excluded from the domain, hence the domain is all real numbers.


As *[tex \LARGE x] either increases or decreases without bound, the value of the denominator increases without bound.  Hence the limiting value of the function is zero.  The smallest value the denominator can assume is when *[tex \LARGE x\ =\ 0] meaning the denominator has the value *[tex \LARGE 49].  This means the largest value the function can attain is *[tex \LARGE \frac{2}{49}]


Hence the range is the interval *[tex \LARGE 0\ <\ y\ \leq\ \frac{2}{49}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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