Question 1359
OK, first we have to takes out both x and 3x from both equations, so lets multiply equation 1 by -3 so then we can takes the x-terms away from both equations:
:
(equation 1)
(-3)(x-2y) = 0(-3)
-3x+6y = 0
:
So now we can use substituion now
-3x+6y = 0
3x+y = 0
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7y = 0
y = 0
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So y is equal to zero