Question 639960
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<b>Step 1:</b>  Find the *[tex \LARGE x]-intercept of *[tex \LARGE y\ =\ -\frac{3}{4}x\ +\ 3].  Substitute the value *[tex \LARGE 0] for *[tex \LARGE y] and solve the resulting equation for *[tex \LARGE x].  Form the ordered pair *[tex \LARGE (a,0)] where *[tex \LARGE a] is the solution you just calculated.


<b>Step 2:</b>  Find the slope of *[tex \LARGE x\ -\ 2y\ -\ 3\ =\ 0].  Since both variables are on the same side of the equals sign, use the following short-cut method:  Divide the opposite of the coefficient on *[tex \LARGE x] by the coefficent on *[tex \LARGE y].


<b>Step 3:</b>  Use the point-slope form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the point calculated in step 1 and *[tex \Large m] is the slope calculated in step 2.


<b>Step 4:</b>  Arrange the result of step 3 into Standard Form, namely *[tex \LARGE Ax\ +\ By\ =\ C].  If any of your coefficients are other than integers, verify that your teacher/instructor/professor's definition of Standard Form allows coefficients that are not integers.  Otherwise, use an appropriate multiplier to convert to integer coefficients.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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