Question 639970
I guess, you have this: {{{1. 1/(x-2)}}}

denominator {{{x-2}}} cannot be equal to zero; so, you right if x=2, then the equation wouldn't work and  the domain is anything but two

or

[{{{-infinity}}},{{{2}}}) U ({{{2}}},{{{infinity}}}]


2. {{{sqrt(x+1)}}}


here also, {{{x+1}}} cannot be equal to zero; so, if {{{x+1=0}}}, then {{{x>=-1}}}

the domain is:


[{{{-1}}},{{{infinity}}}]