Question 639843
<br><font face="Tahoma">Let a be the tens digit, let b be the ones digit.<br>

{{{a+b=8}}} given<br>

{{{b-a=2}}} given<br>

We know that we have to use {{{b-a}}} because the tens digit is smaller than the ones digit.<br>

Now we just need to solve this system of equations by substitution.<br>

{{{b-a=2}}}<br>

{{{b=a+2}}}<br>

{{{a+(a+2)=8}}}<br>

{{{2a+2=8}}}<br>

{{{2a=6}}}<br>

{{{a=3}}}<br>

{{{b-a=2}}}<br>

{{{b-3=2}}}<br>

{{{b=5}}}<br>

Thus, the score should be ab, or 35.<br>

I hope this helps!  :)<br>

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