Question 639811

{{{sin x - cos x =0}}}

As we can see,  the equation is linear, in {{{sin x}}} and {{{cos x}}}. The way of solving this kind of equation is to divide entire equation with "{{{cos x}}}".


{{{sin x/cos x - cos x/cos x =0/cos x}}}


{{{(sin x/ cos x) - 1 = 0}}}


Instead of the ratio {{{sin x/ cos x}}}, we'll use the resulting function, {{{tg x}}}.

The obtained equation is an elementary equation.

{{{tg x - 1 = 0}}}

{{{tg x=1}}}

{{{x= arctg1 +k*pi}}}

{{{x= pi/4 + k*pi}}}