<PRE><B>Question 639794</B>
y x y = 112 = 

{{{y^2 = 112}}}

to get y by itself, take the square root of both sides:

{{{sqrt(y^2) = sqrt(112)}}}

simplify the root by finding what, if any, products of 112 are perfect squares:

16 x 7 = 112, and 16 is a perfect square, so the square root of 112 reduces down to {{{4sqrt(7)}}}

FINAL ANSWER: {{{y = 4sqrt(7)}}}

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