Question 639579
{{{i^(49)}}}


{{{i^(48+1)}}}


{{{i^(48)*i^(1)}}}


{{{i^(4*12)*i^(1)}}}


{{{(i^(4))^(12)*i^(1)}}}


{{{(1)^(12)*i^(1)}}}


{{{1*i^(1)}}}


{{{i^(1)}}}


{{{i}}}


So {{{i^(49)=i}}}