Question 7265
Since we're only looking at the denominators, we don't need to look at the numerators at all.  So if you take that out, this is what we get:


{{{(p^2 + 7p + 10)}}} and {{{(p^2 + 5p + 6)}}}

factorize the two:
{{{(p^2 + 7p + 10)}}}= (p+5)(p+2)


{{{(p^2 + 5p + 6)}}}= (p+3)(p+2)


The LCD= (p+2)(p+3)(p+5), answer=D