Question 639164
you are on the right way, Now you have  to find common denominator, which is {{{(2x-1)(x-3)(x+3)}}}
{{{ 2x/((2x-1)(x-3))-x/((x-3)(x+3))=(2x*(x+3)-x*(2x-1))/((2x-1)(x-3)(x+3))=(2x^2+6x-2x^2+x)/((2x-1)(x-3)(x+3))=7x/((2x-1)(x-3)(x+3)) }}}