Question 639149
The easiest way to solove this is by recognizing that the left side of the equation fits the pattern for sin(A+B):
sin(A+B) = sin(A)cos(B) + cos(A)sin(B)
with the "A" being "3x" and the "B" being "x". So by sin((A+B) the left side is equal to:
sin(3x+x) = -1/2
or simply
sin(4x) = -1/2<br>
This equation we can solve. We should recognize that 1/2 is a special angle value for sin and that the reference angle will be {{{pi/6}}}. Since the sin is negative, we know that the angle terminates in the 3rd or 4th quadrants. Putting the reference angle and the quadrants together we get:
{{{4x = pi + pi/6 + 2pi*n}}} (for the 3rd quadrant)
which simplifies to
{{{4x = 7pi/6 + 2pi*n}}} (for the 3rd quadrant)
and 
{{{4x = -pi/6 + 2pi*n}}} (for the 4th quadrant)
(Instead of {{{-pi/6}}} we could also have used {{{2pi - pi/6}}} or {{{11pi/6}}})<br>
Now we just divide both sides by 4 (or multiply by 1/4):
{{{x = 7pi/24 + pi*n/2}}}
and 
{{{x = -pi/24 + pi*n/2}}}