Question 639152
you are right about - start from common denominator
{{{ 1/x+1/(1+x)=(-3)/(x^2+x)) }}}
{{{ 1/x+1/(1+x)=(-3)/x(x+1)) }}}
{{{( 1+x+x+3)/x(1+x)=0 }}}
{{{( 2x+4)/x(1+x)=0 }}}
The fraction is equal 0, when the numerator is equal 0 and the denominator is not equal 0
{{{2x+4=0}}}
{{{x=-2}}}
Just don't forget to check the answer