Question 639078
Let x be the smaller of the two integers and y be the larger. We are given that:

{{{x+y=4x}}}

{{{y^2-x^2=8y}}}


From equation one we get

{{{y=3x}}} Putting this into equation two we get:

{{{(3x)^2-x^2=8(3x)}}}

{{{x^2-3x=0}}}

So x=3 and y=9. 5he product of these two integers is 27.