Question 639020
factor:
{{{ h^4+64}}}
add sqrt of both terms and expand by squaring:
{{{(h^2+8)^2=(h^4+16h^2+64)-16h^2}}}
{{{(h^2+8)^2-(4h)^2}}}
difference of 2 squares
{{{((h^2+8)+(4h))((h^2+8)-(4h))}}}