Question 639023
Factor:
{{{ 81x^8-34x^4y^4+y^8}}}
Take difference of sqrt of end terms and expand by squaring
{{{(9x^4-y^4)^2=(81x^8-18x^4y^4+y^8)-(16x^4y^4)}}}
{{{(9x^4-y^4)^2-(16x^4y^4)}}}
{{{(9x^4-y^4)^2-(4x^2y^2)^2}}}
difference of 2 squares
{{{((9x^4-y^4)+(4x^2y^2))((9x^4-y^4)-(4x^2y^2))}}}