Question 639022
let the height = x cm
then the base= (x+8) cm
then area = 0.5x(x+8)=120 (qn)
or x^2+8x-240=0 multiplying 2 on both sides & transposing
or x^2+20x-12x-240=0
or x(x+20)-12(x+20)=0
or( x-12)(x+20)=0
or x=12 or -20
so the height of the triangle =12 cm neglecting the -ve value ans