Question 639007

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-6,-10\right)]. So this means that {{{x[1]=-6}}} and {{{y[1]=-10}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-12,-11\right)].  So this means that {{{x[2]=-12}}} and {{{y[2]=-11}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-11--10)/(-12--6)}}} Plug in {{{y[2]=-11}}}, {{{y[1]=-10}}}, {{{x[2]=-12}}}, and {{{x[1]=-6}}}



{{{m=(-1)/(-12--6)}}} Subtract {{{-10}}} from {{{-11}}} to get {{{-1}}}



{{{m=(-1)/(-6)}}} Subtract {{{-6}}} from {{{-12}}} to get {{{-6}}}



{{{m=1/6}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-6,-10\right)] and *[Tex \LARGE \left(-12,-11\right)] is {{{m=1/6}}}