Question 638925

The perimeter of a rectangle is 170 feet. If the length exceeds 5 times the width by 1 foot,then what is the area of the rectangle?


Let width be W
Then length = 5W + 1


Since 2L + 2W = P, we now have: 2(5W + 1) + 2W = 170


10W + 2 + 2W = 170


12W = 168


W, or width = {{{168/12}}}, or 14 ft


Length = 5(14) + 1, or 71 feet ------ Substituting 14 for W


Area = 14(71), or {{{highlight_green(994)}}} sq ft


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