Question 638720


Graph {{{y=-(2/3)x-3}}}

here you have a linear function, and a graph will be a line; so, you need to find two points and plot them and draw the line through them

if {{{x=0}}}...->{{{y=-(2/3)0-3=-3}}}

first point is ({{{0}}},{{{-3}}})

if {{{y=0}}}...->{{{0=-(2/3)x-3}}}....->{{{(2/3)x=-3}}}....->{{{2x=-9}}}....->{{{x=-9/2=-4(1/2)}}}

second point is ({{{-4(1/2)}}},{{{0}}})

{{{ graph( 600, 600, -10, 10, -10, 10, -(2/3)x-3) }}}