Question 638699
log(base 64)x+log(base 8)x+log(base 2)x=9
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{{{log(64,x) + log(8,x) + log(2,x) = 9}}}
64 = 2^6 --> {{{log(64,x) = 6log(2,x)}}}
{{{6log(2,x) + 3log(2,x) + log(2,x) = 9}}}
{{{10log(2,x) = 9}}}
{{{log(2,x) = 0.9}}}
{{{x = 2^0.9}}}
x =~ 1.866066