Question 638604
x1		y1	x2	y2				
3		-1	1	3				
								
slope m =		(y2-y1)/(x2-x1)						
(	3	-	-1	)/(	1	-	3	)
(	4	/	-2	)  				
m=		-2    						 
The required line passes through both the points. So we select one point and plug it with the slope 								
Plug value of  the slope  and point(3,-1) in	
Y	=	m	x	+	b			
-1.00	=	-2    	*	3	+	b		
-1.00	=	-6    	+	b				
b=	-1    	+	6    					
b=	5      							
So the equation  will be								
Y 	=	-2    	x	+	5    			
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