Question 638634
The area of a square increased by 3 is the same as 35 decreased by 7 times the area. Find the are of the square.

LET: x^2 = Area of a Square
WHERE: x^2 is made greater by 3 = 35 made smaller by 7x^2

CALCULATION
x^2+3=35-7x^2
x^2+3-3=35-3-7x^2
x^2=32-7x^2
x^2+7x^2=32-7x^2+7x^2
8x^2/8=32/8=>[x^2=4]
*When I evaluate the answer, it doesn't check.


{{{x^2 = 4}}} 


x, or one side of square = 2, or - 2(ignore)


Original area = {{{x^2}}}, or {{{2^2}}}, or {{{highlight_green(4)}}} square units


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Check
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Area + 3 = 35 - 7(area), OR


4 + 3 = 35 – 7(4)


7 = 35 – 28


7 = 7 (TRUE)


Why do you say that it doesn't check?


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