Question 638585
graph 2 periods for 
y=2sec[3(x-pie/6)] -1 
I know that sec=1/cos but on paper im not sure how to do it, nor apparently on a graphing calculator for I get the graph as a direct line going down.
My mode is in radians too so it isn't that.
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Comment: You were missing a some parentheses.
{{{graph(400,400,-12,12,-10,10,2*(1/cos(3(x-(3.14/6))))-1)}}}
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I need to state the domain for that equation and I thought it would be all real numbers and that the range would be -3_< y_<1 
and no idea how to determine the asymptotes.
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Domain: All Real Numbers except where cosine = 0: 
3(x-(pi/6)) = 0
x = pi/6
Note: that is also where you find a vertical asymptote.
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3(x-(pi/6)) = pi
x-(pi/6) = pi/3
x = pi/2 
Another vertical asymptote at this point.
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Cheers,
Stan H.