<PRE><B>Question 638511</B>
find the position vector for PQ if P=(-2,3) and Q=(14,-2) 
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length = sqrt[(-2-3)^2+(14--2)^2] = sqrt[25+256] = sqrt(281) = 16.76
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tangent of angle = -5/16
tan^-1(-5/16) = -17.35 degrees
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Position vector extends from (0,0) to (5,-16)
or, in polar form (16.76,-17.36)
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Cheers,
Stan H.</PRE>