Question 58657
{{{ A = bh/2 }}}
{{{ A = x^2 + 5x + 6 }}}
{{{ h = x + 3 }}}
Substitute :)
{{{ x^2 + 5x + 6 = (x+3)h/2 }}}
factor the left side
{{{ (x+2)(x+3) = (x+3)h/2 }}}
multiply both sides by {{{ 2/(x+3) }}}
{{{ ((x+2)(x+3))(2/(x+3)) = ((x+3)h/2)(2/(x+3)) }}}
Cancel like terms
{{{ 2(x+2) = h }}}
Distribute
{{{ 2x + 4 = h }}}