<PRE><B>Question 638287</B>
sove these equations: 
1) square root of 8^4 = 8^2 = 64
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2) square root of 3y^4x^9 = sqrt(y^4*x^8*3x) = y^2*x^4*sqrt(3x)
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3) square root of 18/75 = sqrt(9*2)/sqrt(25*3) = (3sqrt(2))/(5sqrt(3))
= (3sqrt(6)/(5sqrt(9) = 3sqrt(6)/15 = (1/5)sqrt(6)
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4) square root of 2x-4=16
Question: Is it sqrt(2x)-4 or is it sqrt(2x-4)?
Cheers,
Stan H.
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