Question 638287
{{{sqrt(8^4)=sqrt((8^2)^2)=8^2=64}}}

{{{3y^4x^9=y^2*x^(9/2)sqrt(3)}}}

{{{sqrt(18/75)=sqrt((18/3)/(75/3))=sqrt(6/25)=sqrt(6/5^2)=sqrt(6)/5}}}

I am not quite sure what you are given here 4) square root of 2x-4=16

if you are given

{{{sqrt(2x-4)=16}}}, then

{{{(sqrt(2x-4))^2=16^2}}}

{{{2x-4=256}}}

{{{2x=256+4}}}

{{{2x=260}}}

{{{x=260/2}}}

{{{x=130}}}