Question 58658
<pre><font size = 5><b> Could someon help me PLZ 
graph y = 2(x+5)^-3 and label 
the vertex and all exact 
intercepts, not to scale on 
the Y axis 
Thank you

There is no "vertex".  There is no x-intercept.  
The y-intercept is

(0, 2/125).  Since the equation is equivalent to

        2 
y = ----------
     (x + 5)³

The denominator becomes zero at x = -5, thus the 
vertical line whose equation is x = -5 is a 
vertical asymptote.

Since the degree of the denominator, 2, is of 
greater than the degree of the numerator, 0, the 
x-axis, whose equatrion is y = 0, is the 
horizontal asymptote.

Find some points and you get the graph below.  
The vertical line is the vertical asymptote. The 
y-intercept (0, 2/125) is so close to the 
origin that it hardly discernable.  The curve 
does not really coincide with the x-axis but is 
so close to it, there is no way to indicate
that it is not actually coinciding with it.

{{{ graph( 200, 200, -8, 2, -1, 1, 2/(x+5)^3) }}}

Edwin</pre>