Question 638010

27x²+ 3x - 10 = 0 solve the following quadratic equation by factoring


{{{27x^2 + 3x - 10 = 0}}}


Factors of 270 (c * a) whose sum is 3 are: 18 & 15, so replacement for b is: (18x - 15x)


{{{27x^2 + 3x - 10 = 0}}} now becomes: {{{27x^2 + 18x - 15x - 10 = 0}}}


9x(3x + 2) - 5(3x + 2) = 0


(9x - 5)(3x + 2) = 0


9x - 5 = 0    or   3x + 2 = 0


9x = 5    or   3x = - 2


{{{highlight_green(x = 5/9)}}}, or {{{highlight_green(x = - 2/3)}}}


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