Question 638010
27x^2+3x-10=0             To solve this, we make use of formular                  {{{x=(-b+-sqrt(b^2-4.a.c))/2*a}}}                      {{{x=(-3+-sqrt(3^2-4*27*-10))/2*27               x=-3+-sqrt(9+1080)/54  x=-3+-sqrt(1089)/54       x=-3+-33/54                      x=-3+33/54 or -3-33/54   x=30/54 or -36/54            x=5/9 or -2/3