Question 638007
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Sice G was going 42 km/hr faster, and she caught up in 2 hours, the "catch-up" distance must have been 84 km.  That's how far R traveled during his 3 hour head start.  Distance divided by rate is time.  You can do the rest of your arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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