Question 637904
Complete for the given equation as directed. (x-3)2/9+(y-6)2/16=1 Center (, ) Length of major axis = Length of minor axis
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{{{(x-3)2/9+(y-6)2/16=1}}}
This is an equation of and ellipse with vertical major axis
Its standard form: {{{(x-h)^2/b^2+(y-k)^2/a^2=1}}}, (a>b), (h,k)=(x,y) coordinates of center
For given equation:
center: (3,6)
a^2=16
a=√16
a=4
length of major axis=2a=8
..
b^2=9
b=√9
b=3
length of minor axis=2b=6