Question 637865
The equation can be expressed as {{{(x-4)^2 + (y+3)^2 = 1}}}.
The graph is a CIRCLE with center at (4,-3) and radius of length {{{sqrt(1)}}} = 1.
Here's the graph:
{{{drawing(300,300,-3,6,-6,3,grid(1),green(circle(4,-3,1)))}}}