Question 58621
a. 3x-y>9
b. 2x-3y< -6

First off, you need to change these problems into slope intercept form (y=mx+b).  To do that for the first problem, subtract 3x from both sides to get -y > -3x + 9.  Now, since your Y value can't be negative, you must multiply by -1 on both sides to get y < 3x - 9 (remember that whenever you multiply or divide by a negative, you change the signs).  For the second problem, you must subtract 2x from both sides to get -3y < -2x - 6.  Now you must divide both sides by -3 to get y > 2/3x + 2 (remember that whenever you multiply or divide by a negative, you change the signs).  Your graph would look something similar to this, but the lines would be dashed because it is < or >.

{{{ graph( 300, 200, -6, 5, -10, 10, y<3x-9, y>0.667x+2) }}}