Question 637519

let's number be {{{n}}}
the sum of the number {{{n}}} and {{{36}} is greater than {{{five}}} {{{times}}} the number; so, we have

{{{n+36>5n}}}

{{{36>5n-n}}}

{{{36>4n}}}

{{{36/4>n}}}

{{{9>n}}}....or...{{{n<9}}}

check: first {{{n<9}}} is {{{n=8}}}

{{{8+36>5*8}}}

{{{44>40}}}