Question 637498

The length {{{L}}}of a soccer field is 40 yards more than its width {{{W}}}.

{{{L=W+40yd}}}..........1

Perimeter {{{P}}} is {{{380yd}}}.


{{{P=2(L+W)}}}........2...substitute {{{L}}} and {{{P}}} 

{{{380yd=2(W+40yd+W)}}}...solve for {{{W}}}

{{{380yd/2=W+40yd+W}}}

{{{190yd=2W+40yd}}}

{{{190yd-40yd=2W}}}

{{{150yd=2W}}}

{{{150yd/2=W}}}

{{{highlight(75yd=W)}}}.......now find the length

{{{L=W+40yd}}}..........1

{{{L=75yd+40yd}}}

{{{highlight(L=115yd)}}}

finally: the area {{{A}}} will be

{{{A=L*W}}}

{{{A=115yd*75yd}}}

{{{A=8625yd^2}}}