Question 637403
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Hi,
h(x) = {{{-2x^2/(x-1)}}}   ||using the Quotient Rule
h '(x) = {{{ ((x-1)*(-4x) - (-2x^2)*1)/(x-1)^2}}}
h '(x) = {{{ ((-4x^2 + 4x) +2x^2)/(x-1)^2}}}
h '(x) = {{{ 2x( 2 - x)/(x-1)^2}}}