<PRE><B>Question 637403</B>
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Use the quotient rule:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h(x)\ =\ \frac{f(x)}{g(x)}]


then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h&#39;(x)\ =\ \frac{f&#39;(x)g(x)\ -\ g&#39;(x)f(x)}{\[g(x)\]^2}]


Use the power rule to determine *[tex \LARGE f&#39;(x)\ =\ -4x] and *[tex \LARGE g&#39;(x)\ =\ 1]


Just put the pieces together and then simplify the expression.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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