Question 637358
If I have this function f (x) = x^3/3 - x^2/2 - 2x + 2 and the tangent to the curve at the point (-1, 19/6) 
What would be the equation of the tangent line? 
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Find the slope of the curve at x = -1
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f'(x) = (1/3)*3x^2 - (1/2)2x - 2
f'(-1) = (1)(1) - (1)(-1) -2 = 1+1-2 = 0
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Equation of line with slope = 0, thru (-1, 19/6)
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Answer y = 19/6
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Cheers,
Stan H.