Question 636970
at a large department store, the average number of years of service was 13.5 with a standard deviation of 6.2 years. If an employee is picked at random, what is the probability that the employee has worked for the company between 10 and 17 years?
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z(10) = (10-13.5)/6.2 = -0.5645 
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z(17) = (17-13.5)/6.2 = 0.5645
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P(10 < x < 17) = P(-0.5645 < z < 0.5645) = 0.4276
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Cheers,
Stan H.