<PRE><B>Question 637165</B>
Given a level of confidence of 95% and a population standard deviation of 14, answer the following:
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n = [z*s/E]^2
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(A) What other information is necessary to find the sample size (n)?
Ans: The Margin of Error
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(B) Find the Maximum Error of Estimate (E) if n = 80. Show all work
Ans: 
80 = [1.96*14/E]^2
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1.96*14/E = sqrt(80)
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E = (1.96*14)/sqrt(80)
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E = 3.07
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Cheers,
Stan H.
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