Question 637065
{{{(-x^3* y^4* w^2)^3 / (-x*y^2 *w^2)^5=-x^(3*3) y^(4*3) w^(2*3) / (-x^5*y^(2*5) *w^(2*5))=x^9*y^12*w^6 / (x^5*y^10*w^10)=x^(9-5)y^(12-10)/w^(10-6)=x^4y^2/w^4}}}