Question 637033
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
4x^2-8x+3=0
(2x-1)(2x-3) = 0  x=intercepts are 1/2, 3/2
vertex form of a Parabola opening up(a>0) or down(a<0), {{{y=a(x-h)^2 +k}}} 
where(h,k) is the vertex  and  x = h  is the Line of Symmetry
4x^2-8x+3= 4(x-1)^2 -4 + 3 = 4(x-1)^2 -1  
V(1,-1), parabola opens Upward, x= 1 the line of symmetry
{{{drawing(300,300,   -6, 6, -6, 6,  blue(line(1,6,1,-6))  , grid(1),
circle(.5, 0,0.3),
circle(1.5, 0,0.3),
circle(1, -1,0.3),
graph( 300, 300, -6, 6, -6, 6,0,4x^2-8x+3))}}}