Question 637021
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Hi, Previously Posted
the <u>hypotenuse</u> of a right triangle exceeds the length of one leg{{{highlight(x)}}} by 1 <u>and</u> is 3less than 4 times the length of the other leg{{{highlight(y)}}}. 
Question states*** hypotenuse can be expressed in two ways...
 x + 1 = 4y-3    Or    {{{x = 4y-4}}}
Using the Pythagorean Theorem
  x^2 + y^2 = (4y-3)^2
{{{(4y-4)^2}}} + y^2 = (4y-3)^2
 y^2 -8y +7 = 0
(y-7)(y-1) = 0,
  y = 7, x = 24 and hypotenuse is  25    {{{x+1}}}