Question 636911
Find slopes of the asymptotes of the hyperbola with the equation 
36 = 9x squared - 4y squared
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rewrite given equation
9x^2-4y^2=36
divide by 36
x^2/4-y^2/9=1
This is a hyperbola with horizontal transverse axis.
Its standard form: {{{(x-h)^2/a^2-(y-k)^2/b^2=1}}}
For given equation:{{{x^2/4-y^2/9=1}}}
a^2=4
a=√4=2
b^2=9
b=√9=3 
slopes of asymptotes for given hyperbola=±b/a=±3/2