Question 636752
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Hi,
If 5in is added to the width of the rectangle , a square with perimeter 36in is Obtained.
 Square has sides = 9in , width{{{highlight(w)}}} of rectangle:  w+5= 9, w = 4in
Question states*** Original Rectangle had a P = 26in
   L + w = 13in
   L + 4 = 13in
       L = 9in

 Dimensions of the Original rectangle were 4in by 9in